35x^2-5x=7x=36

Solution for 35x^2-5x=7x=36 equation:

35x^2-5x=7x=36

We move all terms to the left:

35x^2-5x-(7x)=0

We add all the numbers together, and all the variables

35x^2-12x=0

a = 35; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·35·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*35}=\frac{0}{70}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*35}=\frac{24}{70}
=12/35
$